Solution for the Preparation phase #2
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…s below and above the specified percentile
…contains NA or is NULL
Fix issue quantargo#7: Handling NULL values corrected
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* wrong implementation quantargo#1 * lacking wrong input handling quantargo#2
mannau
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mannau
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Excellent work!
Just a few minor issues regarding documentation and explicit use of any().
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| exportPattern("^[[:alpha:]]+") | |||
| importFrom("stats", "quantile") | |||
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Have you used roxygen2 to generate the file here?
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| transform_log <- function(x){ | ||
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| if( sum(is.na(x)) ){ |
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Why do NA values lead to an error here?
Sidenote: Although correct it would be more explicit to use any(is.na(x))
| else if( length(x) == 0 ){ | ||
| stop("Input x is NULL") | ||
| } | ||
| else if( sum(x <= 0) ){ |
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Again, more explicit to use any(x <= 0). What could be the workaround for negative values here?
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| #' Windsorize | |||
| #' | |||
| #' Do some windsorization. | |||
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Description should be more explicit.
| q <- quantile(x, p) | ||
| x[x >= q] <- q | ||
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| if( sum(is.na(x))){ |
| x[x >= q] <- q | ||
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| if( sum(is.na(x))){ | ||
| stop("Input x contains value NA") |
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Do we need to throw an error here? What could be the workaround for NA values?
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It's my solution