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Work on $\omega_1$ (S35) #1560
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Work on $\omega_1$ (S35) #1560
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yhx-12243
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P76: See Theorem 6.2 in {{zb:1375.54007}}.
Co-authored-by: yhx-12243 <yhx12243@gmail.com>
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Thanks, I included it in the PR. How did you find this by the way? |
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| Consider the open cover $\mathcal{O}=\{[0,a)\mid a \in X\}$. If $X$ were weakly Lindelöf, we would find a countable $\mathcal{U}\subseteq \mathcal{O}$ such that $\bigcup \mathcal{U}$ dense. But then $\bigcup\mathcal{U}=X$, since otherwise we would find an $a \in X$ with $[a,\omega_1)\subseteq X \setminus \bigcup\mathcal{U}$. Therefore $X$ would be a countable union of countable sets and thus countable. |
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| Consider the open cover $\mathcal{O}=\{[0,a)\mid a \in X\}$. If $X$ were weakly Lindelöf, we would find a countable $\mathcal{U}\subseteq \mathcal{O}$ such that $\bigcup \mathcal{U}$ dense. But then $\bigcup\mathcal{U}=X$, since otherwise we would find an $a \in X$ with $[a,\omega_1)\subseteq X \setminus \bigcup\mathcal{U}$. Therefore $X$ would be a countable union of countable sets and thus countable. | |
| Consider the open cover $\mathcal{O}=\{[0,a)\mid a \in X\}$. If $X$ were weakly Lindelöf, we would find a countable $A\subseteq X$ such that $U = \bigcup \{[0, a) : a\in A\}$ is dense in $X$. But if $a_0 = \sup A < \omega_1$, then $U\subseteq [0, a]$, so that $U$ is contained in a proper closed set and is not dense. |
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That |
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In basic language, let |
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This is super great thanks! I think Toronto property should be easy to add with some theorems (for ordinals) and then we completed all ordinals :) |
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@StevenClontz @ccaruvana could one of you review the proximal property for this space? |
Once #1556 and #1455 and this PR are merged, we only need
Proximal (P76)Strongly collectionwise normal (P207), see Theorem Suggestion: Two theorems about GO-spaces and ordinal spaces #1568.for this space (S35) to complete all ordinal spaces.