1.提交斐波那契数列算法的Java版本更新 , 之前的fib(n - 2) + fib (n - 1) 方法的时间复杂度过大 , 无法接收;#13
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miaodongCoder wants to merge 1 commit intoknightsj:masterfrom
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1.提交斐波那契数列算法的Java版本更新 , 之前的fib(n - 2) + fib (n - 1) 方法的时间复杂度过大 , 无法接收;#13miaodongCoder wants to merge 1 commit intoknightsj:masterfrom
miaodongCoder wants to merge 1 commit intoknightsj:masterfrom
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miaodongCoder
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Mar 10, 2023
| return 0; | ||
| public static int Fibonacci( int n ) { | ||
| if (n < 2) { | ||
| return 1; |
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作者你好 , 请检查以下代码 , 如果觉得可以烦请合并我的代码 , 谢谢 , 你的这些LeetCode常见算法题对我的帮助很大 , 我也想尽我自己的一点力 ,帮助这份代码更完善一些;
之前在代码中写了很多注释 ,但是为了和你保持同样的风格我删除了无用的注释 , 烦请合并我的PR
Java版本的代码我都在leetCode上做了检验 , 斐波那契数列做了最多加到30的极限检验;