Skip to content
Open
Changes from all commits
Commits
File filter

Filter by extension

Filter by extension

Conversations
Failed to load comments.
Loading
Jump to
Jump to file
Failed to load files.
Loading
Diff view
Diff view
75 changes: 75 additions & 0 deletions physics/snells_law.py
Original file line number Diff line number Diff line change
@@ -0,0 +1,75 @@
"""
Snell's Law — Refraction Angle Calculation.

Calculates the angle of refraction when light passes between two
media using Snell's Law: n1 * sin(theta1) = n2 * sin(theta2).

Reference: https://en.wikipedia.org/wiki/Snell%27s_law
"""

import math
Comment thread
soradacroi marked this conversation as resolved.


def calculate_refraction_angle(
index_of_refraction_1: float,
index_of_refraction_2: float,
incident_angle_degrees: float,
) -> float:
"""
Calculates the refraction angle of light passing from one medium to another.
The law states that, for a given pair of media, the ratio of the sines
of angle of incidence and angle of refraction s equal to the refractive
index of the second medium with regard to the first which is equal to the
ratio of the refractive indices of the two media, or equivalently, to the
ratio of the phase velocities in the two media.


Formula: n1 * sin(theta1) = n2 * sin(theta2)
or : (sin(theta1) / sin(theta2)) = (n2 / n1)
Where:
n1 = refractive index of the first medium
n2 = refractive index of the second medium
theta1 = angle of incidence
theta2 = angle of refraction

Note: Total Internal Reflection (TIR) occurs when light travels from a
denser medium to a rarer medium and the incident angle exceeds the
critical angle, making refraction impossible.

Sources:
- https://en.wikipedia.org/wiki/Snell%27s_law

-----------------------------------------------------------------------------

>>> calculate_refraction_angle(1.0, 1.33, 60.0)
40.63
>>> calculate_refraction_angle(2.0, 1.0, 30.0)
90.0
>>> calculate_refraction_angle(1.33, 1.0, 60.0)
Traceback (most recent call last):
...
ValueError: Invalid physical inputs: ratio cannot be outside [-1, 1].
>>> calculate_refraction_angle(-1.33, 1.0, 60.0)
Traceback (most recent call last):
...
ValueError: Invalid physical inputs: ratio cannot be outside [-1, 1].
>>>
"""

incident_angle_radians = math.radians(incident_angle_degrees)
refraction_sine = (index_of_refraction_1 / index_of_refraction_2) * math.sin(
incident_angle_radians
)

# If the sine value is approximately 1.0 or -1.0, it's at the critical angle
# We use math.isclose to account for floating-point precision errors
if math.isclose(refraction_sine, 1.0):
Comment thread
soradacroi marked this conversation as resolved.
return 90.0
if math.isclose(refraction_sine, -1.0):
return -90.0

if not -1 <= refraction_sine <= 1:
raise ValueError("Invalid physical inputs: ratio cannot be outside [-1, 1].")

refraction_angle = round(math.degrees(math.asin(refraction_sine)), 2)
return refraction_angle