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When an operator has type parameters that cannot be inferred from the types of its provided arguments, the pretty-printer now automatically displays the type instantiation (e.g., `card<:bool>` instead of `card`). A `PP:showtvi` flag (toggled via `pragma +PP:showtvi`) forces display of type parameters even when they are inferrable.
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alleystoughton
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Looks good to me. I tried things like
lemma test: card = (fun xs : int fset => 0) /\
card = (fun xs : bool fset => 0).
proof.
(*
(card<:int> = fun (_ : int fset) => 0) /\
card<:bool> = fun (_ : bool fset) => 0
*)
alleystoughton
approved these changes
Apr 7, 2026
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When an operator has type parameters that cannot be inferred from the types of its provided arguments, the pretty-printer now automatically displays the type instantiation (e.g.,
card<:bool>instead ofcard).A
PP:showtviflag (toggled viapragma +PP:showtvi) forces display of type parameters even when they are inferrable.