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6 changes: 3 additions & 3 deletions src/content/questions/comp2804/2019-fall-final/8/solution.md
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Expand Up @@ -2,12 +2,12 @@ I guess we can just think, "total possibilities minus possibilities where both O

<ul>
<li> Let S be the set of all possibilities <br/>
We choose 1 position out of the 5 positions for the B: 5 <br/>
We choose 2 position out of the 4 remaining positions for the O: $ \binom{4}{2} $ <br/>
We choose 1 position out of the 6 positions for the B: 6 <br/>
We choose 2 position out of the 5 remaining positions for the O: $ \binom{5}{2} $ <br/>
We choose 1 position out of the 3 remaining positions for the G: 3 <br/>
We choose 1 position out of the 2 remaining positions for the E: 2 <br/>
We choose 1 position out of the 1 remaining positions for the R: 1 <br/>
$ |S| = 5 \cdot \binom{4}{2} \cdot 3 \cdot 2 $
$ |S| = 6 \cdot \binom{5}{2} \cdot 3 \cdot 2 $
<li> Let A be the set of all possibilities where both O's are together <br/>
Let's treat the two O's as one letter <br/>
We have 5 letters: $ G, E, R, B, O $ <br/>
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