Source code of symengine lambdify function?

[Zhyrek]

Hello, I was just wondering if there was a way to dynamically get the source code for a lambdify'd function in symengine? This is one of the last use cases that I need both symengine and sympy for.

E.g.:

import sympy as sp
import symengine as se

x, y = se.symbols("x y")

f = 2*x*y

lambdify_sp = sp.lambdify((x, y), f, "math")
lambdify_se = se.lambdify((x, y), [f])
print("Sympy source")
print(lambdify_sp.__doc__)
print("_________")
print("Symengine source?")
print(lambdify_se.__doc__)
print("_________")

Sympy source
Created with lambdify. Signature:

func(x, y)

Expression:

2*x*y

Source code:

def _lambdifygenerated(x, y):
    return 2*x*y


Imported modules:


_________
Symengine source?
None
_________

[bjodah]

No, currently there's no such way. I guess we could add some method of dumping LLVM IR, if that's helpful. But I think it's almost only useful when debugging.