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SerejaAndDima.java
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59 lines (52 loc) · 1.39 KB
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/* https://codeforces.com/contest/381/problem/A
#greedy #implementation #two-pointer
have two iterator: fist, last
compare the elements at first-index and last-index.
note: the last step when n - odd number / even number.
*/
import java.util.Scanner;
public class SerejaAndDima {
static String calFinalPoints() {
Scanner scanner = new Scanner(System.in);
int n = scanner.nextInt();
int[] arrCard = new int[n];
for (int i = 0; i < n; i++) {
int card = scanner.nextInt();
arrCard[i] = card;
}
scanner.close();
int firstIdx = 0;
int lastIdx = n - 1;
int sumSereja = 0;
int sumDima = 0;
int chooseIdx = 0;
boolean turnFlg = false; // false: turn of Sereja, true: turn of Dima.
while (firstIdx < lastIdx) {
if (arrCard[firstIdx] > arrCard[lastIdx]) {
chooseIdx = firstIdx;
firstIdx += 1;
} else {
chooseIdx = lastIdx;
lastIdx -= 1;
}
if (turnFlg) {
sumDima += arrCard[chooseIdx];
} else {
sumSereja += arrCard[chooseIdx];
}
turnFlg = !turnFlg;
}
// last step
if (firstIdx >= lastIdx) {
if (turnFlg) {
sumDima += arrCard[firstIdx];
} else {
sumSereja += arrCard[firstIdx];
}
}
return sumSereja + " " + sumDima;
}
public static void main(String[] args) {
System.out.println(calFinalPoints());
}
}