-
Notifications
You must be signed in to change notification settings - Fork 40
Expand file tree
/
Copy pathBinaryTreeInorderTraversal.js
More file actions
51 lines (48 loc) · 1.16 KB
/
BinaryTreeInorderTraversal.js
File metadata and controls
51 lines (48 loc) · 1.16 KB
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
45
46
47
48
49
50
51
// Source : https://leetcode.com/problems/binary-tree-inorder-traversal
// Author : Dean Shi
// Date : 2017-02-27
/***************************************************************************************
*
* Given a binary tree, return the inorder traversal of its nodes' values.
*
* For example:
* Given binary tree [1,null,2,3],
*
* 1
* \
* 2
* /
* 3
*
* return [1,3,2].
*
* Note: Recursive solution is trivial, could you do it iteratively?
*
*
***************************************************************************************/
/**
* Definition for a binary tree node.
* function TreeNode(val) {
* this.val = val;
* this.left = this.right = null;
* }
*/
/**
* @param {TreeNode} root
* @return {number[]}
*/
var inorderTraversal = function(root) {
const stack = []
const result = []
while (root) {
if (root.right) stack.push(root.right)
stack.push(root.val)
if (root.left) stack.push(root.left)
root = stack.pop()
while (root !== void(0) && typeof root !== 'object') {
result.push(root)
root = stack.pop()
}
}
return result
};