Attempt 1: Use recursion to return a boolean value that indicates all subtrees have the same value
/**
* Definition for a binary tree node.
* public class TreeNode {
* int val;
* TreeNode left;
* TreeNode right;
* TreeNode() {}
* TreeNode(int val) { this.val = val; }
* TreeNode(int val, TreeNode left, TreeNode right) {
* this.val = val;
* this.left = left;
* this.right = right;
* }
* }
*/
class Solution {
private int count ;
public int countUnivalSubtrees (TreeNode root ) {
if (root == null ) {
return 0 ;
}
count = 0 ;
countUnivalSubtreesRecursion (root );
return count ;
}
private boolean countUnivalSubtreesRecursion (TreeNode root ) {
if (root .left != null && root .right != null ) {
boolean left = countUnivalSubtreesRecursion (root .left );
boolean right = countUnivalSubtreesRecursion (root .right );
if (left && right && root .left .val == root .val && root .right .val == root .val ) {
count ++;
return true ;
} else {
return false ;
}
} else if (root .left != null ) {
boolean left = countUnivalSubtreesRecursion (root .left );
if (left && root .left .val == root .val ) {
count ++;
return true ;
} else {
return false ;
}
} else if (root .right != null ) {
boolean right = countUnivalSubtreesRecursion (root .right );
if (right && root .right .val == root .val ) {
count ++;
return true ;
} else {
return false ;
}
} else {
count ++;
return true ;
}
}
}
Runtime: 0 ms (Beats: 100.00%)
Memory: 41.15 MB (Beats: 98.65%)