Refactor strassen function examples for clarity

Updated examples in the strassen function to improve readability and clarity.

Author: shivansh31414

divide_and_conquer/strassen_matrix_multiplication.py

@@ -119,12 +119,15 @@ def strassen(matrix1: list, matrix2: list) -> list:
         >>> strassen([[2,1,3],[3,4,6],[1,4,2],[7,6,7]], [[4,2,3,4],[2,1,1,1],[8,6,4,2]])
         [[34, 23, 19, 15], [68, 46, 37, 28], [28, 18, 15, 12], [96, 62, 55, 48]]
 
-        >>> strassen([[3,7,5,6,9],[1,5,3,7,8],[1,4,4,5,7]], [[2,4],[5,2],[1,7],[5,5],[7,8]])
-        [[139, 163], [121, 134], [100, 121]]
+       >>> strassen(
+...     [[3,7,5,6,9],[1,5,3,7,8],[1,4,4,5,7]],
+...     [[2,4],[5,2],[1,7],[5,5],[7,8]]
+... )
+
 
         Complexity Notes:
         - Classical matrix multiplication: O(n^3).
-        - Strassen’s algorithm: O(n^(log2(7))) ≈ O(n^2.81).
+        - Strassen's algorithm: O(n^(log2(7))) ≈ O(n^2.81).
         - Strassen reduces the number of multiplications from 8 to 7 per recursion,
           trading them for additional additions/subtractions.
     """