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207.course-schedule.cpp
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101 lines (98 loc) · 2.69 KB
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/*
* @lc app=leetcode id=207 lang=cpp
*
* [207] Course Schedule
*
* https://leetcode.com/problems/course-schedule/description/
*
* algorithms
* Medium (35.31%)
* Likes: 2815
* Dislikes: 144
* Total Accepted: 319.5K
* Total Submissions: 784.2K
* Testcase Example: '2\n[[1,0]]'
*
* There are a total of n courses you have to take, labeled from 0 to n-1.
*
* Some courses may have prerequisites, for example to take course 0 you have
* to first take course 1, which is expressed as a pair: [0,1]
*
* Given the total number of courses and a list of prerequisite pairs, is it
* possible for you to finish all courses?
*
* Example 1:
*
*
* Input: 2, [[1,0]]
* Output: true
* Explanation: There are a total of 2 courses to take.
* To take course 1 you should have finished course 0. So it is possible.
*
* Example 2:
*
*
* Input: 2, [[1,0],[0,1]]
* Output: false
* Explanation: There are a total of 2 courses to take.
* To take course 1 you should have finished course 0, and to take course 0 you
* should
* also have finished course 1. So it is impossible.
*
*
* Note:
*
*
* The input prerequisites is a graph represented by a list of edges, not
* adjacency matrices. Read more about how a graph is represented.
* You may assume that there are no duplicate edges in the input
* prerequisites.
*
*
*/
// @lc code=start
class Solution {
public:
void buildGraph(std::unordered_map<int, std::set<int>>& graph,
const vector<vector<int>>& prerequisites) {
for (int i = 0; i < prerequisites.size(); ++i) {
graph[prerequisites[i][1]].insert(prerequisites[i][0]);
}
}
bool dfs(std::unordered_map<int, std::set<int>>& graph,
std::vector<bool>& visiting_nodes, std::vector<bool>& visited_nodes,
int node) {
visiting_nodes[node] = true;
for (const int& i : graph[node]) {
if (visiting_nodes[i]) {
return false;
}
if (!visited_nodes[i]) {
bool possible = dfs(graph, visiting_nodes, visited_nodes, i);
if (!possible) {
return false;
}
}
}
visiting_nodes[node] = false;
visited_nodes[node] = true;
return true;
}
bool canFinish(int numCourses, vector<vector<int>>& prerequisites) {
std::unordered_map<int, std::set<int>> graph;
buildGraph(graph, prerequisites);
std::vector<bool> visiting_nodes(numCourses, false);
std::vector<bool> visited_nodes(numCourses, false);
bool result = true;
for (int i = 0; i < numCourses; ++i) {
if (!visited_nodes[i]) {
result = dfs(graph, visiting_nodes, visited_nodes, i);
if (!result) {
return false;
}
}
}
return result;
}
};
// @lc code=end