1.js committed

Author: carlosyabreu

Sprint-2/1-key-errors/1.js

@@ -1,20 +1,47 @@
 // Predict and explain first...
 
 // Why will an error occur when this program runs?
+
 // =============> write your prediction here
+/**
+ * Prediction:
+ * An error will occur because the function parameter decimalNumber is being redeclared inside the function body using const. This creates a naming conflict - you can't have a parameter and a local variable with the same name.
+ * Additionally, the console.log(decimalNumber) at the end will cause a ReferenceError because decimalNumber is not defined in the global scope, it's only defined within the function's scope.
+ */
 
 // Try playing computer with the example to work out what is going on
 
+/** Original function:
+ *
+ * function convertToPercentage(decimalNumber) {
+ * const decimalNumber = 0.5;
+ * const percentage = `${decimalNumber * 100}%`;
+ *
+ * return percentage;
+ * }
+ *
+ * console.log(decimalNumber);
+ */
+
+// =============> write your explanation here
+/**
+ * Explanation
+ * The code has two main problems:
+ * Redeclaration error: The function parameter decimalNumber is being redeclared with const decimalNumber = 0.5 inside the function. In JavaScript, it not possible to have a variable with the same name as a parameter in the same scope.
+ * Scope error: The console.log(decimalNumber) at the end is trying to access a variable that only exists inside the function's scope. Variables declared inside functions are not accessible from the outside.
+ * Logic error: Even if the scope issues were fixed, the function always returns "50%" regardless of the input because it overwrites the parameter with 0.5.
+ */
+
+// Finally, correct the code to fix the problem
+// =============> write your new code here
+
 function convertToPercentage(decimalNumber) {
-  const decimalNumber = 0.5;
   const percentage = `${decimalNumber * 100}%`;
-
   return percentage;
 }
 
-console.log(decimalNumber);
-
-// =============> write your explanation here
+// Example usage:
+const decimalNumber = 0.5;
+console.log(convertToPercentage(decimalNumber)); // Output: "50%"
+console.log(convertToPercentage(0.80)); // Output: "80%"
 
-// Finally, correct the code to fix the problem
-// =============> write your new code here